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๐Ÿ“˜ GCSE Maths ยท Notes & worksheet

Vectors.

GCSE Higher (Grades 6-9)board-neutral (AQA / Edexcel / OCR)Worksheet: 19 marks

Notes

Basics

  • A vector has magnitude and direction. In bold or underlined notation: a, or AB with an arrow.
  • Column form: (3, โˆ’2) means 3 right and 2 down.
  • Magnitude of (x, y) is โˆš(xยฒ + yยฒ).
  • Add vectors by adding components. Multiply by a scalar by multiplying each component.
  • Reverse direction = negative: BA = โˆ’AB.

Parallel vectors

Two vectors are parallel if one is a scalar multiple of the other. For example (6, โˆ’9) = โˆ’1.5 ร— (โˆ’4, 6).

Collinear points

Points A, B, C are collinear if AB is parallel to AC, because they share the point A.

Geometric proof method

  1. Write every unknown vector as a journey along known vectors: for example AB = AO + OB = โˆ’a + b.
  2. Use ratios: if P divides AB in the ratio 2:3, then AP = (2/5)AB.
  3. To prove lines are parallel, show one vector is a multiple of the other.
  4. To prove three points are collinear, show two vectors are parallel and share a point.

Worked example

OAB is a triangle with OA = a and OB = b. P lies on AB with AP:PB = 2:3.

  • AB = b โˆ’ a
  • AP = (2/5)(b โˆ’ a)
  • OP = OA + AP = a + (2/5)(b โˆ’ a) = (3/5)a + (2/5)b

Common mistakes

  • Getting directions backwards: AB means "from A to B".
  • Forgetting to simplify the final expression in terms of a and b.
  • Claiming collinear without saying the vectors share a point.

Exam tips

  • Always draw the journey on the diagram.
  • "Show that" proofs need a clear conclusion sentence, such as "so MN is parallel to AB and half its length".

Worksheet

Prints the questions only, without answers. Choose โ€œSave as PDFโ€ in the print window to download.
Diagram placeholderThe diagrams for Q3โ€“Q7 are described in words in the questions. The drawn diagrams are being added to this page.

Total: 19 marks.

  1. a = (3, โˆ’2) and b = (โˆ’1, 4).
    (a) Find 2a โˆ’ 3b. (2)
    (b) Find the exact magnitude of a + b. (1)
  2. Are the vectors (6, โˆ’9) and (โˆ’4, 6) parallel? Give a reason. (2)
  3. OABC is a parallelogram with OA = a and OC = c. M is the midpoint of AB. Find OM in terms of a and c. (2)
  4. OAB is a triangle with OA = a and OB = b. P is on AB such that AP:PB = 2:3. Find OP in terms of a and b. (3)
  5. In triangle OAB, OA = a and OB = b. M is the midpoint of OA and N is the midpoint of OB. Prove that MN is parallel to AB and half its length. (3)
  6. Points A, B and C have position vectors (1, 2), (4, 8) and (โˆ’1, โˆ’2). Show that A, B and C are collinear. (3)
  7. In triangle OAB, OA = a and OB = b. M is the midpoint of AB. G lies on OM with OG:GM = 2:1. Find OG in terms of a and b. (3)

Show mark scheme and answers (tutor copy)

Try the worksheet first, then check your work here.

  1. (a) 2(3, โˆ’2) โˆ’ 3(โˆ’1, 4) = (6, โˆ’4) โˆ’ (โˆ’3, 12) = (9, โˆ’16). (M1, A1)
    (b) a + b = (2, 2), so the magnitude is โˆš(4 + 4) = 2โˆš2. (B1)
  2. (6, โˆ’9) = โˆ’1.5 ร— (โˆ’4, 6), so yes, they are parallel because one is a scalar multiple of the other. (M1, A1)
  3. AB = OC = c, since OABC is a parallelogram. OM = OA + ยฝAB = a + ยฝc. (M1, A1)
  4. AB = b โˆ’ a (B1). AP = (2/5)(b โˆ’ a) (M1). OP = a + (2/5)(b โˆ’ a) = (3/5)a + (2/5)b. (A1)
  5. OM = ยฝa and ON = ยฝb (B1). MN = MO + ON = โˆ’ยฝa + ยฝb = ยฝ(b โˆ’ a) (M1). AB = b โˆ’ a, so MN = ยฝAB. MN is a multiple of AB, so they are parallel and MN is half the length. (A1)
  6. AB = (3, 6) and AC = (โˆ’2, โˆ’4) (M1). (3, 6) = โˆ’1.5 ร— (โˆ’2, โˆ’4) (M1), so AB is parallel to AC. They share the point A, so A, B and C are collinear. (A1)
  7. OM = OA + ยฝAB = a + ยฝ(b โˆ’ a) = ยฝ(a + b) (M1, A1). OG = (2/3)OM = (1/3)(a + b). (A1)